The potential energy of a particle of mass 'm' situated in a unidimensional potential field varies as U(x) = U 0 [1 – cos ax], where U 0 and a are constants. The time period of small oscillations of the particle about the mean position
A
2 π 
B
2 π 
C
2 π 
D
2 π 
Text Solution
Verified by ExpertsThe correct answer is:
C
Restoring force F = 
= 
(u 0 (1-cos ax))
F(x) = – u 0 a sin ax
for small angle sin ax 
ax
F = – u 0 a 2 x
⇒ acc. = 
= –ꞷ 2 x = 
× x
So, Time period T = 2 π 
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